Apabila 2 1 H = 2,009 sma, 3 1 H = 3,016 sma, 4 2 He =
Saluran Edukasion 2024-06-23T17:48:45
Apabila 2 1 H = 2,009 sma, 3 1 H = 3,016 sma, 4 2 He = 4,003 sma, 1 0 n = 1,009 sma dan 1 sma = 931 MeV, hitung energi yang dibebaskan pada reaksi: 2 1 H + 3 1 H -> 4 2 He + 1 0 n
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