lim (y-2)->0 1/y-2[(1/2y^2-y-3)-(2/y(y+1))]= ....
Saluranedukasion 2024-01-26T05:37:00.000Z
![lim (y-2)->0 1/y-2[(1/2y^2-y-3)-(2/y(y+1))]= ....](/_next/image?url=https%3A%2F%2Fi.ytimg.com%2Fvi%2FZsOXJnE_Buc%2Fmaxresdefault.jpg&w=1920&q=75)
lim (y-2)->0 1/y-2[(1/2y^2-y-3)-(2/y(y+1))]= ....
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lim (y-2)->0 1/y-2[(1/2y^2-y-3)-(2/y(y+1))]= ....