Diketahui f(x)={x^2-3x, x>=3 -x^2+3x, 0<=x<3 -x^2-3x,
Saluranedukasion 2023-12-21T22:02:00.000Z
Diketahui f(x)={x^2-3x, x>=3 -x^2+3x, 0<=x<3 -x^2-3x, -3<=x<0 x^2+3x, x<-3. Nilai dari f(-4)+f(-3)+f(0)+f(3)= ....
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