P(n) =1^2+3^2+5^2+...+(2n-1)^2 = n(2n-1)(2n+1)/3

Name: P(n) =1^2+3^2+5^2+...+(2n-1)^2 = n(2n-1)(2n+1)/3
Uploaded: 2023-12-03T04:43:41
Duration: PT7M2.138S
Description: P(n) =1^2+3^2+5^2+...+(2n-1)^2 = n(2n-1)(2n+1)/3