1. 3log3 + 3log2 + 3log21 - 3log14 = 3log((3 x 2 x 21)/14)

Saluranedukasion 2024-04-05T23:39:08.000Z

1. 3log3 + 3log2 + 3log21 - 3log14 = 3log((3 x 2 x 21)/14) = 3log9 = 2 2. 8log16 = (2log16)/(2log8) = 4/3 3. 16log(akar(8)) = (2^4)log(8^(1/2)) = (1/2)/4 2log8 = 1/8 . 3 = 3/8
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