Buktikan bahwa: 2^2+4^2+6^2+...+(2n)^2=sigma i=1 n

Name: Buktikan bahwa: 2^2+4^2+6^2+...+(2n)^2=sigma i=1 n
Uploaded: 2024-04-16T10:02:00
Duration: PT7M23.434S
Description: Buktikan bahwa: 2^2+4^2+6^2+...+(2n)^2=sigma i=1 n ((2i)^2)=(2n(n+1)(2n+1))/3