2+6+12+...+n(n+1)=(n)/(3)(n+1)(n+2)

Name: 2+6+12+...+n(n+1)=(n)/(3)(n+1)(n+2)
Uploaded: 2024-06-04T23:12:00.000Z
Duration: PT5M40.8S
Description: 2+6+12+...+n(n+1)=(n)/(3)(n+1)(n+2)