1+2+4+8+...+128 = .... A. sigma n=1 7 2n B. sigma n=1 7 2^n
Saluranedukasion 2024-05-16T00:16:43
1+2+4+8+...+128 = .... A. sigma n=1 7 2n B. sigma n=1 7 2^n C. sigma n=1 7 2^(n-1) D. sigma n=1 8 2^(n-1) E. sigma n=1 8 2^n
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