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a. Jika F(x) = (2x - 4)^2 - x^2, hitung F(2), F(0), dan

Pertanyaan

a. Jika F(x) = (2x - 4)² - x², hitung F(2), F(0), dan F(-2). b. Jika F(x) = (3x - 1)² + 2x², hitung F(4), F(0), dan F(-4).

Solusi

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a. F(2) = -4, F(0) = 16, F(-2) = 60. b. F(4) = 153, F(0) = 1, F(-4) = 201.

Pembahasan

Untuk soal ini, kita akan menghitung nilai fungsi F(x) pada nilai x yang diberikan. a. Jika F(x) = (2x - 4)² - x²: - Menghitung F(2): F(2) = (2(2) - 4)² - (2)² F(2) = (4 - 4)² - 4 F(2) = (0)² - 4 F(2) = 0 - 4 F(2) = -4 - Menghitung F(0): F(0) = (2(0) - 4)² - (0)² F(0) = (0 - 4)² - 0 F(0) = (-4)² - 0 F(0) = 16 - 0 F(0) = 16 - Menghitung F(-2): F(-2) = (2(-2) - 4)² - (-2)² F(-2) = (-4 - 4)² - 4 F(-2) = (-8)² - 4 F(-2) = 64 - 4 F(-2) = 60 b. Jika F(x) = (3x - 1)² + 2x²: - Menghitung F(4): F(4) = (3(4) - 1)² + 2(4)² F(4) = (12 - 1)² + 2(16) F(4) = (11)² + 32 F(4) = 121 + 32 F(4) = 153 - Menghitung F(0): F(0) = (3(0) - 1)² + 2(0)² F(0) = (0 - 1)² + 2(0) F(0) = (-1)² + 0 F(0) = 1 + 0 F(0) = 1 - Menghitung F(-4): F(-4) = (3(-4) - 1)² + 2(-4)² F(-4) = (-12 - 1)² + 2(16) F(-4) = (-13)² + 32 F(-4) = 169 + 32 F(-4) = 201

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Topik: Fungsi
Section: Menghitung Nilai Fungsi

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