limit x mendekati 1/8 pi (sin^2 2x - cos^2 2x)/(sin 2x-cos

Saluranedukasion 2024-04-09T05:56:43.000Z

limit x mendekati 1/8 pi (sin^2 2x - cos^2 2x)/(sin 2x-cos 2x)=...
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limit x mendekati 1/8 pi (sin^2 2x - cos^2 2x)/(sin 2x-cos 2x)=...