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Diketahui matriks A = (-2 1 3 3 2 5 2 1 -2), tentukan

Pertanyaan

Diketahui matriks A = [[-2, 1, 3], [3, 2, 5], [2, 1, -2]], tentukan adj(A)!

Solusi

Verified

Adj(A) = [[-9, 5, -1], [16, -2, 19], [-1, 4, -7]]

Pembahasan

Untuk mencari adjoin (adj(A)) dari matriks A, kita perlu menghitung matriks kofaktornya terlebih dahulu, lalu mentranspose matriks kofaktor tersebut. Matriks A = [ -2 1 3 ] [ 3 2 5 ] [ 2 1 -2 ] Menghitung minor untuk setiap elemen: Minor A11 = (2*-2) - (5*1) = -4 - 5 = -9 Minor A12 = (3*-2) - (5*2) = -6 - 10 = -16 Minor A13 = (3*1) - (2*2) = 3 - 4 = -1 Minor A21 = (1*-2) - (3*1) = -2 - 3 = -5 Minor A22 = (-2*-2) - (3*2) = 4 - 6 = -2 Minor A23 = (-2*1) - (1*2) = -2 - 2 = -4 Minor A31 = (1*5) - (3*2) = 5 - 6 = -1 Minor A32 = (-2*5) - (3*3) = -10 - 9 = -19 Minor A33 = (-2*2) - (1*3) = -4 - 3 = -7 Matriks Minor M = [ -9 -16 -1 ] [ -5 -2 -4 ] [ -1 -19 -7 ] Menghitung kofaktor dengan aturan tanda (+ - + / - + - / + - +): Kofaktor C = [ -9 16 -1 ] [ 5 -2 4 ] [ -1 19 -7 ] Adjoin(A) adalah transpose dari matriks kofaktor: Adj(A) = Cᵀ = [ -9 5 -1 ] [ 16 -2 19 ] [ -1 4 -7 ]
Topik: Matriks
Section: Adjoin Matriks

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