integral ((3x^3+5x^2+3x+1)(x^3+x^2+x)^9)/(x+1) dx=

Saluran Edukasion 2024-05-19T13:41:43

integral ((3x^3+5x^2+3x+1)(x^3+x^2+x)^9)/(x+1) dx=
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integral ((3x^3+5x^2+3x+1)(x^3+x^2+x)^9)/(x+1) dx=