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Jika diketahui matriks A=(5 8 2 3), B=(2 -1 4 6), dan C=(2
Pertanyaan
Jika diketahui matriks A=(5 8 2 3), B=(2 -1 4 6), dan C=(2 4 6 -1), maka hasil dari A^t+B^t-C adalah...
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[[5, 2], [1, 10]]
Pembahasan
Pertama, kita cari transpose dari matriks A dan B: Matriks A = [[5, 8], [2, 3]] A^t (transpose dari A) = [[5, 2], [8, 3]] Matriks B = [[2, -1], [4, 6]] B^t (transpose dari B) = [[2, 4], [-1, 6]] Matriks C = [[2, 4], [6, -1]] Sekarang kita hitung A^t + B^t: A^t + B^t = [[5, 2], [8, 3]] + [[2, 4], [-1, 6]] A^t + B^t = [[5+2, 2+4], [8+(-1), 3+6]] A^t + B^t = [[7, 6], [7, 9]] Terakhir, kita hitung (A^t + B^t) - C: (A^t + B^t) - C = [[7, 6], [7, 9]] - [[2, 4], [6, -1]] (A^t + B^t) - C = [[7-2, 6-4], [7-6, 9-(-1)]] (A^t + B^t) - C = [[5, 2], [1, 10]]
Topik: Matriks
Section: Operasi Matriks
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