1/3 [log 2 + log x - log(3x^2+1)] = ....
Saluran Edukasion 2024-07-15T11:31:43
![1/3 [log 2 + log x - log(3x^2+1)] = ....](/_next/image?url=https%3A%2F%2Fi.ytimg.com%2Fvi%2F3Aqw3f3zDXs%2Fmaxresdefault.jpg&w=1920&q=75)
1/3 [log 2 + log x - log(3x^2+1)] = ....
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1/3 [log 2 + log x - log(3x^2+1)] = ....