Tuliskan persamaan kuadrat yang mempunyai penyelesaian

a. x^2 + 6x + 8 = 0, b. x^2 - x - 12 = 0, c. x^2 + (1/6)x - 1/18 = 0, d. x^2 + (11/3)x - 4/3 = 0

Pembahasan

a. Akar -4 dan -2: (x - (-4))(x - (-2)) = (x+4)(x+2) = x^2 + 6x + 8 = 0
b. Akar -3 dan 4: (x - (-3))(x - 4) = (x+3)(x-4) = x^2 - x - 12 = 0
c. Akar -1/3 dan 1/6: (x - (-1/3))(x - 1/6) = (x+1/3)(x-1/6) = x^2 + (1/3 - 1/6)x - (1/3)(1/6) = x^2 + (1/6)x - 1/18 = 0
d. Akar -4 dan 1/3: (x - (-4))(x - 1/3) = (x+4)(x-1/3) = x^2 + (4 - 1/3)x - 4/3 = x^2 + (11/3)x - 4/3 = 0