Hitunglah: a. (2/9)^5:[(2/9)^2]^3 b.

a. 9/2, b. 1

Pembahasan

Untuk soal a: (2/9)^5 : [(2/9)^2]^3 = (2/9)^5 : (2/9)^(2*3) = (2/9)^5 : (2/9)^6 = (2/9)^(5-6) = (2/9)^(-1) = 9/2.
Untuk soal b: (221/(8^2))^(18) : [(221/(8^2))^3]^6 = (221/64)^18 : (221/64)^(3*6) = (221/64)^18 : (221/64)^18 = (221/64)^(18-18) = (221/64)^0 = 1.